6x^2+26x-665=0

Solution for 6x^2+26x-665=0 equation:

6x^2+26x-665=0

a = 6; b = 26; c = -665;
Δ = b2-4ac
Δ = 262-4·6·(-665)
Δ = 16636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16636}=\sqrt{4*4159}=\sqrt{4}*\sqrt{4159}=2\sqrt{4159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{4159}}{2*6}=\frac{-26-2\sqrt{4159}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{4159}}{2*6}=\frac{-26+2\sqrt{4159}}{12}
$